Chapter 10 Practical Geometry Exercise 10.3


Question 1.
Construct ∆DEF such that DE = 5 cm, DF = 3 cm and m ∠DEF = 90°.


Solution:
Steps of construction:
(i) Draw DF = 3 cm.
(ii) Draw an angle of 90° at D and cut DE = 5 cm.
(iii) Join EF.
(iv) EPF is the required triangle.
Using SAS property

Question 2.
Construct an isosceles triangle in which the lengths of each of its equal sides is 6.5 cm and the angle between them is 110°.


Solution:
Steps of construction:
(i) Draw AB = 6.5 cm.
(ii) Draw angle of 110° at A and cut AC = 6.5 cm.
(iii) Join C to B.
(iv) CAB is the required triangle.
[Using SAS criterion]

Question 3.
Construct ∆ABC with BC = 7.5 cm, AC = 5 cm and m ∠C = 60°.


Solution:
Steps of construction:
(i) Draw BC = 7.5 cm.
(ii) Draw ∠C = 60° such that AC = 5 cm.
(iii) Join A to B.
(iv) ABC is the required triangle.
[Using SAS Criterion]

NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.3 Q1
NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.3 Q2
NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.3 Q2.1
NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.3 Q2.2
NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.3 Q3
NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.3 Q3.1

Chapter 10 Practical Geometry Exercise 10.3