Chapter 11 Perimeter and Area Exercise 11.2
Question 1.
Find the area of each of the following parallelograms:
![NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.2 1](http://104.199.181.145/wp-content/uploads/2022/04/ncert-solutions-for-class-7-maths-chapter-11-perim-2.png)
Solution:
(a) Area of the parallelogram
= base × altitude = 7 cm × 4 cm
= 28 cm2
(b) Area of the parallelogram
= base × altitude = 5 cm × 3 cm
= 15 cm2
(c) Area of the parallelogram
= base × altitude = 2.5 cm × 3.5 cm
= 8.75 cm2
(d) Area of the parallelogram
= base × altitude = 5 cm × 4.8 cm
= 24.0 cm2
(e) Area of the parallelogram
= base × altitude = 2 cm × 4.4 cm
= 8.8 cm2
Question 2.
Find the area of each of the following triangles:
![](https://rajboardexam.in/wp-content/uploads/2022/07/image-200.png)
Question 3.
Find the missing values:
S.No. | Base | Height | Area of the parallelogram |
(a) | 20 cm | 246 cm2 | |
(6) | 15 cm | 154.5 cm2 | |
(c) | 8.4 cm | 48.72 cm2 | |
(d) | 15.6 | 16.38 cm2 |
Solution:
(a) Area of the parallelogram =b × h
246 = 20 × h
(b) Area of the parallelogram = b × h
154.5 = b × 15
![](https://rajboardexam.in/wp-content/uploads/2022/07/image-201.png)
(c) Area of the parallelogram = b × h
48.72 = b × 8.4
(d) Area of the parallelogram = b × h
16.38 = 15.6 × h
![](https://rajboardexam.in/wp-content/uploads/2022/07/image-202.png)
Question 4.
Find the missing values:
Base | Height | Area of the triangle |
15 cm | — | 87 cm2 |
— | 31.4 mm | 1256 mm2 |
22 cm | — | 170.5 cm2 |
![](https://rajboardexam.in/wp-content/uploads/2022/07/image-203.png)
Question 5.
PQRS is a parallelogram. QM is the height of Q to SR and QN is the height from Q to PS. If SR = 12 cm and QM = 7.6 cm. Find:
(a) the area of the parallelogram PQRS
(b) QN, if PS = 8 cm
![](https://rajboardexam.in/wp-content/uploads/2022/07/image-204.png)
Solution:
(a) Area of the parallelogram PQRS
= SR × QM (∵ Area = Base × Height)
= 12 cm × 7.6 cm
= 91.2 cm2
(b) Area of the parallelogram PQRS
![](https://rajboardexam.in/wp-content/uploads/2022/07/image-205.png)
![](https://rajboardexam.in/wp-content/uploads/2022/07/image-206.png)
Question 7.
∆ABC is right angled at A. AD is perpendicular to BC. If AB = 5 cm, BC = 13 cm and AC = 12 cm, find the area of ∆ABC. Also find the length of AD.
![](https://rajboardexam.in/wp-content/uploads/2022/07/image-207.png)
Solution:
Area of right triangle ABC
![](https://rajboardexam.in/wp-content/uploads/2022/07/image-208.png)
![](https://rajboardexam.in/wp-content/uploads/2022/07/image-209.png)
![NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.2 A1](http://104.199.181.145/wp-content/uploads/2022/04/ncert-solutions-for-class-7-maths-chapter-11-perim-45.png)
![NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.2 A2](http://104.199.181.145/wp-content/uploads/2022/04/ncert-solutions-for-class-7-maths-chapter-11-perim-50.png)
![NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.2 A3](http://104.199.181.145/wp-content/uploads/2022/04/ncert-solutions-for-class-7-maths-chapter-11-perim-53.png)
![NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.2 A4](http://104.199.181.145/wp-content/uploads/2022/04/ncert-solutions-for-class-7-maths-chapter-11-perim-54.png)
![NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.2 A5](http://104.199.181.145/wp-content/uploads/2022/04/ncert-solutions-for-class-7-maths-chapter-11-perim-59.png)
![NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.2 A6](http://104.199.181.145/wp-content/uploads/2022/04/ncert-solutions-for-class-7-maths-chapter-11-perim-61.png)
![NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.2 A7](http://104.199.181.145/wp-content/uploads/2022/04/ncert-solutions-for-class-7-maths-chapter-11-perim-63.png)